In
module 2 we studied molecular genetics. Here we are concerned with classical
genetics, which is the study of inheritance of characteristics at the whole
organism level. It is also known as transmission genetics or Mendelian
genetics, since it was pioneered by Gregor Mendel.
Mendel (1822-1884) was an Austrian monk at Brno monastery. He was a keen gardener and scientist, and studied at Vienna University, where he learnt statistics. He investigated inheritance in pea plants and published his results in 1866. They were ignored at the time, but were rediscovered in 1900, and Mendel is now recognised as the “Father of Genetics”. His experiments succeeded where other had failed because:
A typical experiment looked like this:
Mendel made several conclusions from these experiments:
1. There are no mixed colours (e.g. pink), so this disproved the widely-held blending theories of inheritance that characteristics gradually mixed over time.
2. A characteristic can disappear for a generation, but then reappear the following generation, looking exactly the same. So a characteristic can be present but hidden.
3. The outward appearance (the phenotype) is not necessarily the same as the inherited factors (the genotype) For example the P1 red plants are not the same as the F1 red plants.
4. One form of a characteristic can mask the other. The two forms are called dominant and recessive respectively.
5. The F2 ratio is always close to 3:1. Mendel was able to explain this by supposing that each individual has two versions of each inherited factor, one received from each parent. We’ll look at his logic in a minute.
6.
Mendel’s factors are now called genes and the two alternative
forms are called alleles. So in the example above we would say that
there is a gene for flower colour and its two alleles are “red” and
“white”. One allele comes from each parent, and the two alleles are found
on the same position (or locus) on the homologous chromosomes. With two
alleles there are three possible combinations of alleles (or genotypes) and
two possible appearances (or phenotypes):
|
Genotype |
Name |
Phenotype |
|
RR |
homozygous dominant |
red |
|
rr |
homozygous recessive |
white |
|
Rr, rR |
heterozygous |
red |
A
simple breeding experiment involving just a single characteristic, like
Mendel’s experiment, is called a monohybrid cross. We can now explain
Mendel’s monohybrid cross in detail.
At fertilisation any male gamete can fertilise any female
gamete at random. The possible results of a fertilisation can most easily be
worked out using a Punnett Square as shown in the diagram. Each of the
possible outcomes has an equal chance of happening, so this explains the 3:1
ratio (phenotypes) observed by Mendel.
This
is summarised in Mendel’s First Law, which states that individuals
carry two discrete hereditary factors (alleles) controlling each
characteristic. The two alleles segregate (or separate) during meiosis,
so each gamete carries only one of the
two alleles.
You can see an individual’s phenotype, but you can’t see its genotype. If an individual shows the recessive trait (white flowers in the above example) then they must be homozygous recessive as it’s the only genotype that will give that phenotype. If they show the dominant trait then they could be homozygous dominant or heterozygous. You can find out which by performing a test cross with a pure-breeding homozygous recessive. This gives two possible results:
If the offspring all show the dominant trait then the parent must be homozygous dominant.
If
the offspring are a mixture of phenotypes in a 1:1 ratio, then the parent
must be heterozygous.
Mendel never knew this, but we can explain in detail the relation between an individual’s genes and its appearance. A gene was originally defined as an inherited factor that controls a characteristic, but we now know that a gene is also a length of DNA that codes for a protein. It is the proteins that actually control phenotype in their many roles as enzymes, pumps, transporters, motors, hormones, or structural elements. For example the flower colour gene actually codes for an enzyme that converts a white pigment into a red pigment:
Sometimes
the gene actually codes for a protein apparently unrelated to the phenotype.
For example the gene for seed shape in peas (round or wrinkled) actually codes
for an enzyme that synthesises starch! The functional enzyme makes lots of
starch and the seeds are full and rounded, while the non-functional enzyme
makes less starch so the seeds wrinkle up.
This table shows why the allele that codes for a functional protein is usually dominant over an allele that codes for a non-function protein. In a heterozygous cell, some functional protein will be made, and this is usually enough to have the desired effect. In particular, enzyme reactions are not usually limited by the amount of enzyme, so a smaller amount will have little effect.
|
Genotype |
Gene
product |
Phenotype |
|
homozygous dominant (RR) |
all functional enzyme |
red |
|
homozygous recessive (rr) |
no functional enzyme |
white |
|
heterozygous (Rr) |
some functional enzyme |
red |
|
|
|
|
In
module 2 we saw that sex is determined by the sex chromosomes (X and Y). Since
these are non-homologous they are called heterosomes, while the other 22 pairs
are called autosomes. In humans the sex chromosomes are homologous in females
(XX) and non-homologous in males (XY), though in other species it is the other
way round. The inheritance of the X and Y chromosomes can be demonstrated
using a monohybrid cross:
This
shows that there will always be a 1:1 ratio of males to females. Note that
female gametes (eggs) always contain a single X chromosome, while the male
gametes (sperm) can contain a single X or a single Y chromosome. Sex is
therefore determined solely by the sperm. There are techniques for separating
X and Y sperm, and this is used for planned sex determination in farm animals
using IVF.
The
X and Y chromosomes don’t just determine sex, but also contain many other
genes that have nothing to do with sex determination. The Y chromosome is very
small and seems to contain very few genes, but the X chromosome is large and
contains thousands of genes for important products such as rhodopsin (a protein in the membrane of a photoreceptor cell in
the retina of the eye, basically a light absorbing pigment), blood
clotting proteins and muscle proteins. Females have two copies of each gene on
the X chromosome (i.e. they’re diploid), but males only have one copy of
each gene on the X chromosome (i.e. they’re haploid). This means that the
inheritance of these genes is different for males and females, so they are
called sex linked characteristics.
The
first example of sex linked genes discovered was eye colour in Drosophila fruit flies. Red eyes (R) are dominant to white eyes (r)
and when a red-eyed female is crossed with a white-eyed male, the offspring
all have red eyes, as expected for a dominant characteristic (left cross
below). However, when the opposite cross was done (a white-eye male with a
red-eyed female) all the male offspring had white eyes (right cross below).
This surprising result was not expected for a simple dominant characteristic,
but it could be explained if the gene for eye colour was located on the X
chromosome. Note that in these crosses the alleles are written in the form XR
(red eyes) and Xr (white eyes) to show that they are on the X
chromosome.
Males
always inherit their X chromosome from their mothers, and always pass on their
X chromosome to their daughters.
Another well-known example of a sex-linked characteristic is colour blindness in humans. 8% of males are colour blind, but only 0.7% of females. The genes for green-sensitive and red-sensitive rhodopsin are on the X chromosome, and mutations in either of these lead to colour blindness. The diagram below shows two crosses involving colour blindness, using the symbols XR for the dominant allele (normal rhodopsin, normal vision) and Xr for the recessive allele (non-functional rhodopsin, colour blind vision).
Other
examples of sex linkage include haemophilia, premature balding and muscular
dystrophy.
In most situations (and all of Mendel’s experiments) one allele is completely dominant over the other, so there are just two phenotypes. But in some cases there are three phenotypes, because neither allele is dominant over the other, so the heterozygous genotype has its own phenotype. This situation is called codominance or incomplete dominance. Since there is no dominance we can no longer use capital and small letters to indicate the alleles, so a more formal system is used. The gene is represented by a letter, and the different alleles by superscripts to the gene letter.
A good example of codominance is flower colour in snapdragon (Antirrhinum) plants. The flower colour gene C has two alleles: CR (red) and CW (white). The three genotypes and their phenotypes are:
|
Genotype |
Gene
product |
Phenotype |
|
homozygous RR |
all functional enzyme |
red |
|
homozygous WW |
no functional enzyme |
white |
|
heterozygous (RW) |
some functional enzyme |
pink |
In this case the enzyme is probably less active, so a smaller amount of enzyme will make significantly less product, and this leads to the third phenotype. The monohybrid cross looks like this:
Note
that codominance is not an example of “blending inheritance” since the
original phenotypes reappear in the second generation. The genotypes are not
blended and they still obey Mendel’s law of segregation. It is only the
phenotype that appears to blend in the heterozygotes.
Another example of codominance is sickle cell haemoglobin in humans. The gene for haemoglobin Hb has two codominant alleles: HbA (the normal gene) and HbS (the mutated gene). There are three phenotypes:
|
HbAHbA |
Normal. All haemoglobin is normal, with normal red blood cells. |
|
HbAHbS |
Sickle cell trait. 50% of the haemoglobin in every red blood cell is normal, and 50% is abnormal. The red blood cells are slightly distorted, but can carry oxygen, so this condition is viable. However these red blood cells cannot support the malaria parasite, so this phenotype confers immunity to malaria. |
|
HbSHbS |
Sickle cell anaemia. All haemoglobin is abnormal, and molecules stick together to form chains, distorting the red blood cells into sickle shapes. These sickle red blood cells are destroyed by the spleen, so this phenotype is fatal. |
Other
examples of codominance include coat colour in cattle (red/white/roan), and
coat colour in cats (black/orange/tortoiseshell).
An unusual effect of codominance is found in Manx cats, which have no tails. If two Manx cats are crossed the litter has ratio of 2 Manx kittens to 1 normal (long-tailed) kitten. The explanation for this unexpected ratio is explained in this genetic diagram:
The gene S actually controls the development of the embryo cat’s spine. It has two codominant alleles: SN (normal spine) and SA (abnormal, short spine). The three phenotypes are:
|
SNSN |
Normal. Normal spine, long tail |
|
SNSA |
Manx Cat. Last few vertebrae absent, so no tail. |
|
SASA |
Lethal. Spine doesn’t develop, so this genotype is fatal early in development. The embryo doesn’t develop and is absorbed by the mother, so there is no evidence for its existence. |
Many
human genes also have lethal alleles, because many genes are so essential for
life that a mutation in these genes is fatal. If the lethal allele is
expressed early in embryo development then the fertilised egg may not develop
enough to start a pregnancy, or the embryo may miscarry. If the lethal allele
is expressed later in life, then we call it a genetic disease, such as muscular
dystrophy or cystic fibrosis.
An
individual has two copies of each gene, so can only have two alleles of any
gene, but there can be more than two alleles of a gene in a population. An
example of this is blood group in humans. The red blood cell antigen is coded
for by the gene I (for isohaemaglutinogen), which has three alleles IA,
IB and IO. (They are written this way to show that they
are alleles of the same gene.) IA and IB are codominant,
while IO is recessive. The possible genotypes and phenotypes are:
|
Phenotype (blood
group) |
Genotypes |
antigens
on red blood cells |
plasma
antibodies |
|
A |
IAIA, IAIO |
A |
anti-B |
|
B |
IBIB, IBIO |
B |
anti-A |
|
AB |
IAIB |
A and B |
none |
|
O |
IOIO |
none |
anti-A and anti-B |
The cross below shows how all four blood groups can arise from a cross between a group A and a group B parent.
Other
examples of multiple alleles are: eye colour in fruit flies, with over 100
alleles; human leukocyte antigen (HLA) genes, with 47 known alleles.
So far we have looked at the inheritance of a single gene controlling a single characteristic. This simplification allows us to understand the basic rules of heredity, but inheritance is normally much more complicated than that. We’ll now turn to the inheritance of characteristics involving two genes. This gets more complicated, partly because there are now two genes to consider, but also because the two genes can interact with each other. We’ll look at three situations:
2 independent genes, controlling 2 characteristics (the dihybrid cross).
2 independent genes controlling 1 characteristic (polygenes)
2 interacting genes controlling 1 characteristic (epistasis)
Mendel also studied the inheritance of two different characteristics at a time in pea plants, so we’ll look at one of his dihybrid crosses. The two traits are seed shape and seed colour. Round seeds (R) are dominant to wrinkled seeds (r), and yellow seeds (Y) are dominant to green seeds (y). With these two genes there are 4 possible phenotypes:
|
Genotypes |
Phenotype |
|
RRYY, RRYy, RrYY, RrYy |
round yellow |
|
RRyy, Rryy |
round green |
|
rrYY, rrYy |
wrinkled yellow |
|
rryy |
wrinkled green |
Mendel’s
dihybrid cross looked like this:
All
4 possible phenotypes are produced, but always in the ratio 9:3:3:1. Mendel
was able to explain this ratio if the factors (genes) that control the two
characteristics are inherited independently; in other words one gene does not
affect the other. This is summarised in Mendel’s second law (or the law of
independent assortment), what states that alleles of different genes are
inherited independently.
We can now explain the dihybrid cross in detail.
The gametes have one allele of each gene, and that allele can end up with either allele of the other gene. This gives 4 different gametes for the second generation, and 16 possible genotype outcomes.
There are 4 genotypes that all give the same round yellow phenotype. Just like we saw with the monohybrid cross, these four genotypes can be distinguished by crossing with a double recessive phenotype. This gives 4 different results:
|
Original
genotype |
Result
of test cross |
|
RRYY |
|
|
RRYy |
1 round yellow : 1 round green |
|
RrYY |
1 round yellow : 1 wrinkled yellow |
|
RrYy |
1 round yellow : 1 round green: 1 wrinkled yellow: 1 wrinkled green |
|
|
|
Sometimes
two genes at different loci (i.e. separate genes) can combine to affect one
single characteristic. An example of this is coat colour in Siamese cats. One
gene controls the colour of the pigment, and black hair (B) is dominant to
brown hair (b). The other gene controls the dilution of the pigment in the
hairs, with dense pigment (D) being dominant to dilute pigment (d). This gives
4 possible phenotypes:
|
Genotypes |
Phenotype |
F2
ratio |
|
BBDD, BBDd, BbDD, BbDd |
“seal” (black dense) |
9 |
|
BBdd, Bbdd |
“blue” (black dilute) |
3 |
|
bbDD, bbDd |
“chocolate” (brown dense) |
3 |
|
bbdd |
“lilac” (brown dilute) |
1 |
The
alleles are inherited in exactly the same way as in the dihybrid cross above,
so the same 9:3:3:1 ratio in the F2 generation is produced. The only
difference is that here, we are looking at a single characteristic, but with a
more complicated phenotype ratio than that found in a monohybrid cross.
A
more complex example of a polygenic character is skin colour in humans. There
are 5 main categories of skin colour (phenotypes) controlled by two genes at
different loci. The amount of skin pigment (melanin) is proportional to the
number of dominant alleles of either gene:
|
Phenotype (skin
colour) |
Genotypes |
No.
of dominant alleles |
F2
ratio |
|
Black |
AABB |
4 |
1 |
|
Dark |
AaBB, AABb |
3 |
4 |
|
Medium |
AAbb, AaBb, aaBB |
2 |
6 |
|
Light |
Aabb, aaBb |
1 |
4 |
|
White (albino) |
aabb |
0 |
1 |
Some
other examples of polygenic characteristics are: eye colour, hair colour, and
height. The important point about a polygenic character is that it can have a
number of different phenotypes, and almost any phenotypic ratio
In epistasis, two genes control a single character, but one of the genes can mask the effect of the other gene. A gene that can mask the effect of another gene is called an epistatic gene (from the Greek meaning “to stand on”). This is a little bit like dominant and recessive alleles, but epistasis applies to two genes at different loci. Epistasis reduces the number of different phenotypes for the character, so instead of having 4 phenotypes for 2 genes, there will be 3 or 2. We’ll look at three examples of epistasis.
1.
Dependent genes.
In mice one gene controls the production of coat pigment, and black
pigment (B) is dominant to no pigment (b). Another gene controls the dilution
of the pigment in the hairs, with dense pigment (D) being dominant to dilute
pigment (d). This is very much like the Siamese cat example above, but with
one important difference: the pigment gene (B) is epistatic over the dilution
gene (D) because the recessive allele of the pigment gene is a mutation that
produces no pigment at all, so there is nothing for the dilution gene to
affect. This gives 3 possible
phenotypes:
|
Genotypes |
Phenotype |
F2
ratio |
|
BBDD, BBDd, BbDD, BbDd |
Black (black dense) |
9 |
|
BBdd, Bbdd |
Brown (black dilute) |
3 |
|
bbDD, bbDd, bbdd |
White (no pigment) |
4 |
2.
Enzymes in a pathway. In a certain variety of sweet pea there are
two flower colours (white and purple), but the F2 ratio is 9:7. This is
explained if the production of the purple pigment is controlled by two enzymes
in a pathway, coded by genes at different loci.
Gene
P is epistatic over gene Q because the recessive allele of gene P is a
mutation that produces inactive enzyme, so there is no compound B for enzyme Q
to react with. This gives just two possible phenotypes:
|
Genotypes |
Phenotype |
F2
ratio |
|
PPQQ, PPQq, PpQQ, PpQq |
Purple |
9 |
|
PPqq, Ppqq, ppQQ, ppQq, ppqq |
White |
7 |
3. Duplicate Genes. This occurs when genes at two different loci make enzyme that can catalyse the same reaction (this can happen by gene duplication). In this case the coloured pigment is always made unless both genes are present as homozygous recessive (ppqq), so the F2 ratio is 15:1.
|
Genotypes |
Phenotype |
F2
ratio |
|
PPQQ, PPQq, PpQQ, PpQq, PPqq, Ppqq, ppQQ, ppQq |
Purple |
15 |
|
ppqq |
White |
1 |
So
epistasis leads to a variety of different phenotype ratios.
In the monohybrid cross, the F2 ratio was 3:1, and with the dihybrid cross the ratio was 9:3:3:1. These are expected ratios, calculated from genotypes of the parental generation - assuming independent assortment, no sex linkage, or codominance. In real crosses the offspring produced depends on chance fusion of gametes (fertilisation), leading to observed ratios. There are differences between expected and observed rat